电大 高起点 数学小抄.doc

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1、专业好文档电子科技大学入学测试机考高起点 数学 模拟题1若全集,集合,则为( ) (A)(B) (C)(D)标准答案:D2设集合A1,4,5,7,B2,3,4,5,则( ) (A)4,5AB (B)4,5AB (C)4,5AB (D)4,5AB标准答案:A3下列命题是真命题的是( ) (A) 且 (B)若,则 (C)方程的解是或 (D)存在,使标准答案:A4已知a、b、c均不为零,x1、x2是关于x方程的两个实根,则 等于( ) (A) (B) (C) (D) 标准答案:A5若抛物线的顶点在原点,焦点坐标,则抛物线方程为( ) (A) (B) (C) (D) 标准答案:B6已知函数,那么的值为

2、( ) (A)4(B)2 (C)1(D)标准答案:B7是的( ) (A)充分而不必要条件 (B)必要而不充分条件 (C)充要条件 (D)既不充分也不必要条件标准答案: B8函数与的图像( ) (A)关于x轴对称 (B)关于y轴对称 (C)关于原点对称 (D)关于x轴和y轴都不对称标准答案:B9106.函数(为常数)的最小周期是( )A B. C. D. 标准答案B10已知数列,则是它的( ) (A)第18项(B)第19项 (C)第20项(D)第21项标准答案:A11实轴长为10,焦点分别为(0,),(0,)的双曲线方程是( ) (A) (B) (C) (D) 标准答案:D12已知a, b的值分

3、别为( ) (A) 20,0(B) 0,20 (C)0,10(D) 20,10标准答案:A13已知平行线和,则与这两条平行线距离相等的点的轨迹是( ) (A) (B) (C) (D) 标准答案:D14不等式的解集是( ) (A) (B) (C) (D) 标准答案:D15下列函数在区间(0,1)内单调递减的是( ) (A) (B) (C) (D) 标准答案:C16已知,则f(1)的值为( ) (A) 2(B) 1 (C) 0(D) 3标准答案:B17在DABC中,b7,c5,a4,这个三角形是( ) (A)钝角三角形(B)直角三角形 (C)锐角三角形(D)不能推判上述结论标准答案:A18在等差数

4、列中,已知,则( ) (A)a30(B)a40 (C)a50(D)各项都不为0标准答案:B19任选一个不大于20的正整数,它恰好是3的整数倍的概率是( ) (A)(B) (C)0.3(D)0.2标准答案:C20如果直线与直线关于直线对称,那么( ) (A) (B) (C) (D) 标准答案:A21四名学生和两名教师排成一排,若教师不相邻且不排在两端,则不同的排法有( ) (A)96种(B)144种 (C)72种(D)240种标准答案:B22已知椭圆上一点P到椭圆一个焦点的距离为3,则P到另一个焦点的距离为( ) (A)2(B)3 (C)5(D)7标准答案:D23已知数列的前n项和为Sn,且则S

5、n等于( ) (A) (B) (C) (D) 标准答案:B24经过点B(0,3)且与直线垂直的直线方程为( ) (A)(B) (C)(D) 标准答案:B25化简的结果是( ) (A)(B) (C)(D)标准答案:D26A,B,C,D,E五人并排站成一排,如果B必须站在A的左边(A,B可以不相邻),那么不同的排法共有( ) (A)24种(B)60种 (C)90种(D)120种标准答案:B27函数( ) (A)是奇函数 (B)是偶函数 (C)既不是奇函数又不偶函数 (D)既是奇函数又是偶函数标准答案:A28已知角a3,则a的终边在( ) (A)第一象限(B)第二象限 (C)第三象限(D)第四象限标

6、准答案:B29设a是第二象限角,且,则是( ) (A)第一象限角(B)第二象限角 (C)第三象限角(D)第四象限角标准答案:C30设的值等于( ) (A)(B) (C)(D)标准答案:A315个人站成一排照像,甲、乙两个恰好站在两边的概率是( ) (A)(B) (C)(D)标准答案:A32过点P(1,2)且与直线垂直的直线的方程为( ) (A) (B) (C) (D) 标准答案:B33设则a的取值范围是( ) (A) (B) (C) (D) 标准答案:C34已知,那么的值为( ) (A)(B) (C)1(D) 标准答案:B35若( ) (A) (B) 2 (C) -3(D) 3标准答案:A36

7、如果抛物线方程,那么它的焦点到准线的距离等于( ) (A)16(B)8 (C)4(D)2标准答案:B37的导数是( ) (A) (B) (C) (D) 标准答案:D38函数与在同一坐标系中图像之间的关系是( ) (A)关于x轴对称 (B)关于y轴对称 (C)关于原点对称 (D)关于直线对称标准答案:B39从一幅52张扑克牌中,任抽一张得到黑桃的概率是( ) (A)(B) (C) (D)标准答案:C41设椭圆过点,则其焦距是( ) (A)(B) (C)(D)标准答案:D42若双曲线上一点P到右焦点的距离为8,则P点到左准线的距离是( ) (A)(B) (C)(D)标准答案:A43函数的最小值是(

8、 ) (A)4(B)0 (C)1(D)3标准答案:C44的最小正周期是( ) (A)(B) (C)(D)标准答案:B45等于( ) (A) 0(B) 1 (C) n(D) n+1标准答案:A46已知角的终边通过点( ) (A) (B) (C ) (D) 标准答案:D47设成等比数列,则x等于( ) (A)4或4(B)4或6(C )4或6(D)4或6标准答案:B48已知直线l与直线垂直,则l的斜率为( ) (A)(B) (C)(D) 标准答案:D49函数的最小正周期是( ) (A)(B) (C)(D)标准答案:B50设一个盒子中有5件产品,其中3个为正品,2件为次品,现从中每次取一件,取后不放回

9、,再从中又取一件,则两次都取得正品的概率为( )(A) (B) (C) (D) 标准答案C51.设集合 B= 则集合的关系是( )(A) (B) (C) (D)三个答案都不对标准答案C52.设集合直线,B=。则当( )时,与相交。(A) (B)是多元素集 (C)是单元素集 (D)以上结论都不对标准答案C53不等式 的解集为( )(A),-1) (B) (C)(-1,) (D)以上答案都不对 标准答案C54不等式()的解集为( )(A),-21)+) (B)(-21, 21)(C)(-,-21) (D)(21, +)答案A55.若函数与函数y=互为反函数,则与值为( )(A) (B) (C) (

10、D) 答案B56.设集合 , 则=( )A, -5,3 B, (-5,3) C, (-5, +) D, 5,3答案A57.设集合 B=1,,3 且A( )(A) 2, (B) 1,2,3 C,1, ,3 (D) 1, ,2答案B58.函数与的图像之间的关系是( )(A)关于直线对称 (B)关于轴对称 (C) 关于原点对称, (D) 重合答案A59.函数的定义域为( )(A) (-,-3) (B) (-3,4) (C) (4,+) (D) (-,-3)(4, +)答案D60.函数的定义域为( )(A) , +) (B) +) (C) (1, 2)+ ) (D) )答案A61.图像经过点(0,1)

11、的函数是( )(A) (B) (C) (D) 答案C62.图像过点(1,0)的函数是( )(A) (B) (C) (D) 答案C63.在定义域内为单调增函数的是( )(A) (B) (C) (D) 答案A64.在定义域内为单调减函数的是( )(A) (B) (C) (D) 答案C65.设,则下面正确的关系是( )(A) (B) (C) (D) 都不正确答案C66.设,则下面正确的关系是( )(A) (B) (C) (D)答案B67.若,则下列成立的式子是( )(A)( (B) (C) (D) 答案C68.若, 则满足( )(A) (B) (C) (D)答案B69.函数的定义域是( )(A) (

12、4 ,+) (B) (-,-4) (C) (-,-4)4,+) (D) (-4, 4)答案C70.sin21+sin22+sin289的值应属于区间( )(A) (43,44) (B) (44,45) (C) (45, 46) (D) (47,48)答案B71.若=,且sin的值是( )(A) (B) (C) (D) 答案A72.的值应为( )(A) (B) (C) D) 答案A73的值等于( )(A) (B) (C) (D) 答案B75,已知tan 的值是( )(A) -3 (B) (C) (D) 答案A76,若,则下面关系式中正确的是( )(A) (B) (C) (D) 答案A78.化简的

13、值为( )(A) (B) (C) -1 (D) 1答案C79,化简后得结果为( )(A) sin (B) cos (C) (D) 答案 D80化简的结果为( )(A) 0 (B) -1 (C) 1 (D) 1 答案C81,化简的结果为( )(A) (B) (C)1 (D) -1答案C82.化简)后结果为( )(A) (B) (C) (D) 答案C83.计算得结果( )(A) 3 (B) 2 (C) -1 (D) 1答案D84已知,则的值为(A) (B) (C) (D) 答案B85化简的结果为( )(A) (B) (C) (D)答案B86函数的周期为( )(A) (B) (C)2 (D)答案B8

14、7的振幅为( )(A) (B) (C) (D)1答案D88已知曲线方程,在下面给的点中,在曲线上的点应为( )(A) (B)() (C) (D)(3,-4) 答案D89方程表示的曲线是(A)双曲线 (B)椭圆 (C)抛物线 (D)直线 答案B90,直线和,则 的夹角为( )(A) (B) (C) (D) 答案A91,已知直线与直线垂直则应为( )(A) -6 (B) (C) 6 (D) 答案A92数列1,-3,5,-7,9,-11前100项之和为( )(A)-100 (B)-200 (C)100 (D)200答案A93在3与9之间插入两个正数,使这四个数成等差数列,则插入的数字和为( )(A)

15、13 (B)12 (C) 11 (D)10答案B94在等差数列中已知,则( )(A)34 (B)72 (C)-24 (D)36答案D95已知等比数列,,则其通项( )(A) (B)(C) (D)答案D96若三数成等差数列,则三个数应为( )(A)11,8,5 (B)3,0,-3 (C)-5,-8,11 (D)7,4,1答案A97已知三个数成等比数列,其积为64,其和为14,则三个数应为( )(A)8,4,2 (B)2,4,8 (C)8,4,2或2,4,8 (D)3,5,6答案C98已知,则的导数( )(A) (B) (C) (D)答案C99已知,则的导数为(A) (B) (C) (D)答案A1

16、00函数的单调减区间和极小值分别为( )(A)(-1,2),-2 (B)(-2,1),-10 (C)(-1,1),2 (D)(-1,1),-2答案D1017人排成一排,甲站两端的概率为( )(A) (B) (C) (D) 答案C1026名歌手站成一排表演,若甲不排头,则有( )种不同排法。(A)120 (B)720 (C)600 (D)240 答案C103用0,1,2,3,5,7这6个数字,能组成没有重复数字的三位数有( )个。(A)120 (B)100 (C)20 (D)218答案B104从1,2,3,4,5中任取3个组成三位数,则所得三位数为偶数的概率为( )(A) (B) (C) (D)

17、 答案BIf we dont do that it will go on and go on. We have to stop it; we need the courage to do it.His comments came hours after Fifa vice-president Jeffrey Webb - also in London for the FAs celebrations - said he wanted to meet Ivory Coast international Toure to discuss his complaint.CSKA general dir

18、ector Roman Babaev says the matter has been exaggerated by the Ivorian and the British media.Blatter, 77, said: It has been decided by the Fifa congress that it is a nonsense for racism to be dealt with with fines. You can always find money from somebody to pay them.It is a nonsense to have matches

19、played without spectators because it is against the spirit of football and against the visiting team. It is all nonsense.We can do something better to fight racism and discrimination.This is one of the villains we have today in our game. But it is only with harsh sanctions that racism and discrimina

20、tion can be washed out of football.The (lack of) air up there Watch mCayman Islands-based Webb, the head of Fifas anti-racism taskforce, is in London for the Football Associations 150th anniversary celebrations and will attend Citys Premier League match at Chelsea on Sunday.I am going to be at the m

21、atch tomorrow and I have asked to meet Yaya Toure, he told BBC Sport.For me its about how he felt and I would like to speak to him first to find out what his experience was.Uefa hasopened disciplinary proceedings against CSKAfor the racist behaviour of their fans duringCitys 2-1 win.Michel Platini,

22、president of European footballs governing body, has also ordered an immediate investigation into the referees actions.CSKA said they were surprised and disappointed by Toures complaint. In a statement the Russian side added: We found no racist insults from fans of CSKA.Baumgartner the disappointing

23、news: Mission aborted.The supersonic descent could happen as early as Sunda.The weather plays an important role in this mission. Starting at the ground, conditions have to be very calm - winds less than 2 mph, with no precipitation or humidity and limited cloud cover. The balloon, with capsule attac

24、hed, will move through the lower level of the atmosphere (the troposphere) where our day-to-day weather lives. It will climb higher than the tip of Mount Everest (5.5 miles/8.85 kilometers), drifting even higher than the cruising altitude of commercial airliners (5.6 miles/9.17 kilometers) and into

25、the stratosphere. As he crosses the boundary layer (called the tropopause),e can expect a lot of turbulence.The balloon will slowly drift to the edge of space at 120,000 feet ( Then, I would assume, he will slowly step out onto something resembling an Olympic diving platform.Below, the Earth becomes

26、 the concrete bottom of a swimming pool that he wants to land on, but not too hard. Still, hell be traveling fast, so despite the distance, it will not be like diving into the deep end of a pool. It will be like he is diving into the shallow end.Skydiver preps for the big jumpWhen he jumps, he is ex

27、pected to reach the speed of sound - 690 mph (1,110 kph) - in less than 40 seconds. Like hitting the top of the water, he will begin to slow as he approaches the more dense air closer to Earth. But this will not be enough to stop him completely.If he goes too fast or spins out of control, he has a s

28、tabilization parachute that can be deployed to slow him down. His team hopes its not needed. Instead, he plans to deploy his 270-square-foot (25-square-meter) main chute at an altitude of around 5,000 feet (1,524 meters).In order to deploy this chute successfully, he will have to slow to 172 mph (27

29、7 kph). He will have a reserve parachute that will open automatically if he loses consciousness at mach speeds.Even if everything goes as planned, it wont. Baumgartner still will free fall at a speed that would cause you and me to pass out, and no parachute is guaranteed to work higher than 25,000 feet (7,620 meters).cause there电子科技大学 高起点 数学 第 17 页 共 17 页

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