《电力系统分析中国电力出版社苏小林闫晓霞版.docx》由会员分享，可在线阅读，更多相关《电力系统分析中国电力出版社苏小林闫晓霞版.docx（133页珍藏版）》请在三一办公上搜索。
1、第一章T 220x110/1001 I：,10x105/100242T6 110 _1103：10xl.l -1T,T. 35 二 354：6xl.l 6I-I 解:发电机G额定电压：IoX = 10.5KV100变压器额定变比：T220 r(110 ) :(35 X ) = 220:121:38.521001001-2解：(1)：发电机G： 10. 5KV变压器高低压侧额定电压：T 121 T 110HO T 35351,:, 1=, 1 9=10.5351.1 38.53 10l.l 11(2)变压器实际变比：T 121x(1 + 2.5%) 124 TlIO T 35(1-5%) 33.
2、2511：=， ， 1=10.510.52 38.53 101.1111-3 解：日用电量：W = 702 + 504 + 802 + 1004 + 802 + 904 + 1204 + 702 = 2040(MWh)W 2040日平均负荷：Pqv = HL =上= 85(MW) av 2424P 25负荷率：/ = - = = 0.708PM 120P 50最小负荷率：/=皿=0.417PmaX 12()W 11-4 解：Tmax = -(100 2000 + 60 4000 + 30 2760) = 5228(h)max 匕I(X)第二章2-1解:线路长度为65km,属短线路，不计分布性参
3、数= K = W = O 0 km),S 300D111 = Dab Dac Dhc = V6000 600012000 = 7559.5(mm)x1 =0.1445 Ig+ 0.0157 = 0.4215( / km)7 58b =106 =2.7106 (SZkm)ig4r.-./? = r1 = 0.10565 = 6.825()X xll = 0.421565 = 27.3975()8 = Z = 2.7 X10-6 * 65 = 1.755 X104 (S)等效电路:6.825+ j27.3975二二 j0.877510-4S2-2解：（1）不计分布性参数31.54x400= 0.0
4、197(km)D111 = Dab Dac Dbc = Vl 20001200024000 = 15119.1(mm)Vr-J12-J13 614 = V13.624004004002 = 187.38(mm)X1 = 0.1445Ig= 0.1445Ig% n187.384= 0.279(km)7.58IgDm106 =3.975 106 (SZkm).? = = 0.0197120 = 2.364()X =x1 = 0.279120 = 33.48()B = bJ = 3.975XlO-6 120 = 4.77X10-4(S)等效电路:2.364+ j33.48I1 j2.385 104S
5、(2)不计分布性参数r. = = - 315- = 0.0197(/km),S 4400Dlll = Dab Dac Dhc = V14000 1400014000 = 14000(mm)req = rd2 .九d, = N13.62 X 450 X 450X 450后=204.68(mm)a 1,z1c1 Dm 0.0157 八f/口 140000.0157 八“八小八、X1 =0.1445 Ig i2- += 0.1445 Ig+ - = 0.269( / km)7 58b、=-106 =4.131106 (SZkm)的Yeq:. = = 0.0197120 = 2.364()X =xl
6、= 0.269120 = 32.28()B = i = 4.131106120 = 4.9572 104 (S) 2-3 解： = = 0.1200 = 20()X = Lsl = 250203 200= 125.66()B = 2 / = 2) X 50 X 0.01X10-6 * 200 = 6.28 X104(S)I27002/: =l-x1-= 1-25021032-500.01106- = 0.974 r 1 1 33k=-(x1Z?, -= 0.987, E=I+ 再4 L = LOO7X1 612Z, = krR-vkxX = 0.974 20 + j.987 X125.66 =
7、 19.48 + jl 24.026()Y, = JkbB = jl .007 6.28 104 = j6.324 W4(S)20 + jl25.66oEZZJOO短线路等效电路1=1= j3.1410-4S =C20 + jl25.66中等长度线路等效电路= j3.16210-4S =19.48 + jl24.026长线路等效电路2-4 解:XT1 UkooUli _ 1 10.5 IlO22 100 SN 2 100GT = 2 - = 2IO(W ；10181000x1 IO263.525()2.976 10-6(S)= 2x* = l-型等效电路:O-jl .488 105 S2.97
8、610 6S3.63 j63.525I 12-5 解:%=g(%-2+”3-2.3)= 93(kW)=-3-3) = 52(kW)&=(+%-3 - -)= 65(kW)RTl =PsU1i 931212Rf3IOOOS 1000 202/12U = 5212121000S 1000 202生 U； 65l2f=3.404()1.903()IOOOS； 1000 202=2.379()% % = ； (USf % + UST % -42.3 %)= 1 1 42 % = ； (UST % 0S2.3 % - - %) = -0.5S3% = -(Us3T % + US2.3 % - US- %
9、)= 7XTlX2 =IOO SNUs2%U；IOO ST3 一IOO SNBr 二IOO% 0%SN11 1212=XIOO 20-0.5 1212=80.526()IOO201212=-3.66()=XIOO 2043.31000 12123.46x20100(7；1001212= 51.244()2.957 106 (S)=4.726 IO5(S)等效电路图:1.903-j3.662-6 解:SPs2-3 = (l)2 %一3 = 4啜-3 = 1080(kW), GT= 4GL= 1380(kW) 3N& =1-3-2-3) = 312.5(kW)& = (+ k - -)= lZ5(
10、kW)% = g(%-3 + %.3 - .2)= l67.5(kW)312.52202IOoOSt1000902= 1.867()2 = 票=E)Rt 3=6.379()1067.5x2202IOOOS- - IOoOX 9()2S么2 3% = (,% = 2U 3% = 24.2,么3 I % = 2U1 I % = 37.2 d3N% % = g (US2 % + USX % -42_3 %)=11542 % = : (US2 % Us2.3 % - %) = -l5Us3% = (Us3 % + u* 3%一4 2%) = 25.7 Iox J x ,A 一11.5 2202 = 6
11、1.844()100 SN10090一.S2%u;A n -1.5 2202 =X=-8.067()100 SN10090_ -S3% U； T425.7 2202 =X= 138.209()100 SN10090GT庶 104100 叫 1000 2202= 2.149x10-6(S)B 二-%SN IOo0.65901002202= 1.209 IO5(S)等效电路图:0.075 -j8.0676379+jl3S2091.867 +j61.844C0(2.149-jl2.09) IO-6S2-7 解:(1)以22OkV电压作为基本级RTPSUtIOOOS. 620x242211000 X
12、2402X = 4% /二 14/422 IOOSN 100 240G 二一二 185, IoOO 1000 2422B _ _ %SN 0.5x240 _TL 10(Wn - 100 2422 34.162()= 3.159106(S)2.049 105 (S)Ps2-3= ()2-3= = 592(kW), k = 4% = 880(kW)% = %匕.2 + %一3 一 之一3)= 4835(kW)& T+ -匕.3)= 1955(kW)% = ；(&-3 G2.3 一 匕-2)= 3965(kW)RrI =Rt2483.5x22021000S 10001802195.5x22()2 I
13、OOOS； IOoOXI 8()2 396.5x22()2=0.722()=0.292()IOOOS；10001802=0.592()Us% = JUSl一2% + Us3T% 一 42_3%)= 14.95Us2% = ； (USJ2% + 0S2-3% - Us3T%) = -0.95XTl100 SN14.95 2202、= 61.844()100180X2Us2%U1-0.95 2202S/。qqc100 SNX乙 QD4HSZJ100180X39.05 2202 C 、=X= 24.334()100 180100 SNGt22- 4 1 AOylrr6qIOo-*+. 11V ( D
14、)1000 2202Us3 = - (Us3 % + us2-3 % - US12 %)= 9.05B20%5n _ 0.8180 100(72 -ioo22O2= 2.975 105 (S)Ll: R1 = rll = 0.08 60 = 4.8()X1 二戈=0.417x60= 25.02(。)B1 = / = 2.91 106 60 = 1.746 X104 (S)22()L2: R2 =0.13250()2 =21.818()X2 = 0.405 50 ()2 = 66.942()220B2 =2.7610650(-)2 =4.1745 IO5 (S)等效电路:0.63 + j34.l
15、621(4.8 + j25.O2)r-=)-L jI.746104S :U1s(2)选取SB=I0MVA,4= 22OkV, Zb =- = 48.4(), Yb =- = 0.02066(S) SBUgT1: R；=殳= 0.013 X；=丘= 0.706,= il = 1.529 104, = = 9.918104ZBZBYq%：杵=殳 = 0.015 g=限= 0.006 =% = 0.012ZBZBZBX=&L = 0.831, X = 0.13250 = 0.499Uii1152X； =x2- = 0.40550 = 1.531 UlH52U21 1 C2B* = b4 = 2.76
16、 106 50 = 1.825 103-2 SB1000等效电路为:E。S+e0TO-XJ-Te0.011 + j.583- (0.091 + j.473)To-Xa_迩一) InTI-C)T j9.236IO3 -2-8解：（1）计算线路参数:7: RTPSUk _ 4101212XT =GTlBTl =10005； Us%U100 SN凡100(Wn，0%SN _IOoU；-,=0.417() 10001202=X = 12.811()100 12099 4,：7 = 6.789 10-6 (S) 100012120.61201001212PsW4.91810 5(S)300l IO2IO
17、OOS；2000X 6320.457()4I % = ； (UST % US3T % -42.3 %)= 1 42 % = J (US2 % + US2.3 % - dm % ) = 0.543% = (S3-I % US2.3% - %) = 6XTl 二100 SNX2IOO SX3Us3%UIOO SN10 HO2 X 100 630.5 HO2 =100 636 HO2 =X100 63= 19.206()=0.96()li.524()84.7Br2IOO喏 /0 %SN 100(721000 IlO27 106 (S)急爱= 6.248XmlvL2:lv叫=1 =0.422x80 =
18、 33.76(Q)X1 = x11 =0.42980 = 34.32()B1 =11 = 2.66 i 06 80 = 2.128 104 (S)R2 = r2l2 = 0.422 50 = 21.1()X2 = x2l2 =0.42950 = 21.45()B2 =b2l2 =2.6610-6 50 = 1.33l04(S)R3 =*=0.42260 = 25.32()X3 = x3l3 = 0.42960 = 25.74()B3 = b3l3 = 2.66 XIO-6 X 60 = 1.596 X10-4 (S)RT =PsU1 148i IO2XtGt3 =B3 =IOO SN4Io(W
19、； 0%SN . 1001/2 100031.5210.5 HO2 100 31.51.805()40,333()IR S:-7 = 3.182x10-6(S)1000 HO20.831,5 =2.O83xlO 5(S)IOOxIIO2等效电路图:S9-OLI68C9)-0I=0.457+ jl9.206J20.457+ jO.96it1C二+W。(2)标幺制下，按精确计算法计算，选取Tj-S5b =IOOOMVa, Uti =HOkV, ZB=-L = I2.1(。)，Yti =- = 0.083(S) SBUA解=生=Oo34 X；=丘=ZBTZB1.059,G；=且= 8.18l()T,
20、屏=坛= 5.925l()T %AT2:Rx=RK=R= 0.038, X1 ZB=五=1.587, X2 = 0,079, X-J3 = 0.952ZBG2 = - = 8.434 10,2 =S2= -j 1 5.4 10-4 2102 = -jl 1.907(MVA), _ F=7.528 W4GpX，.R1- = - = 0.149, X；=-=ZBZB3.333,Gx= 3.834xlq m=% = 2.51xl(4-B-BlRVR；=L = 2.79, X；=L = 2.836ZBZB8；=殳= 2.564x10-3L2:R；=生= 1.744 X；=区= ZbZb1.773,房=
21、1.602x10-3R； = & = 2.093, X；=区= ZBZB2.127,8； = = 1.923x10-32-9解：选取 SB=IOoOMVA, UB=UaVG：xd = 1.628-= 0.1628SN1000T1:X；_ si% SB10.5 1000 3U= 0.875100 SN100 1201000A1:$=xd T = O.4X 100 - = 3.025U：V115T.：X 二二42% SB10.5 1000 一 5-=X= 1.167100 SN10090R：X*二 X = 0.05l = 1.091Kr3nU 京34 6.32L2:忘=6/? 7-= F0.45
22、25x5 = 283.4476.32* 巧=X / 组=2 2 U2 VZ av0.08x25x9 = 50.3916.32等效电路图：j0.1628j.875j3.025jL167jl.091283.447r*v-v- I -vtv-v I -VVVV I ALj50.391rwvIII第三章3-1解：（1）计算线路参数：R = R =l = i0.13 100 = 6.5()X=X1=1 = 0.412100 = 21.05()B = 2B.= 2b xl = 22.710S = -Bt72X =-5.4104210 21.05 = -1.194(kV)100 = 5.41O4(S)-U
23、S： 6.5 + j21.055；$14-S j2.7104Sj2.7104SS2 =-j(2 =-j-5.41042102 =-jll.907(MVA) =52+5y2 = 40 + j30 - jl 1.907 = 40 + jl 8.093(M VA)Sz = - +,7(R + jX) = 4* +18,93- /s + j2i.05) = 0.284 +jO.92(MVA) ( 7ZlUSl, = +Sz =40+jl 8.093 + 0.284 + j.92 = 40.284 jl9.013(MVA)U =耶心 二 40x65 + 18093x2L05 = 3 05 y U2210
24、, P；X-Q,R 4021.05-18.0936.5 Q yicz wxU = -= 3.45(kV)U2210U = J(U2+AU)2+92 = 213.08(kV)S =-jq2 =-jl5.410-4213.082 =-jl2.259(MVA)Sx =S1, + S1 = 40.284 + jl9.013- jl 2.259 = 40.284+ j6.754(M VA) 电压向量图为：犯BU) H =x 5.4 x 10-4 x 21ox 6.5 = 0.369(kV) 22Ul = (210-1.194)2 + 0.3692 = 208.806(kV)Sz = . J22 (R +
25、 jX) =(C7厂(6.5 + j21.05) = 0.021 + j0.068(MVA)SS2+5z = -jl 1.907 + 0.021 + j0.068 = 0.021-jl 1.839(MVA)5=-j5.4104208.8062 =-jl 1.772(MVA)S1 =Slz + S = 0.021 - jl 1.839 - jl 1.772 = 0.021 - j23.611(MVA)3-2解：计算变压器参数(归算到高压侧)：U=35x” = 500(kV)ZTl ( 2 m Z、?400 + jl94口 产nA Z3P90 + j56%3 = 26 = (F)2 94.9 =
26、1647.569(kW) 53n3602-3 =2 =()2 = 1616319(kW) 53n3601=+ - &3) = 218.675(kW)鸟2 = ；(/一2 Ps2.3- %.3)= 187.425(kW)=- - %,)= 1428,894(kW)Ssi % = ； Os % Ssl3 % - %) = 13.1 42 % = J (Sl.2 % + 42.3 % - U3 %)= 一2.3 43 % = ； (UsL3 % + % - %) = 31.5RTI =218.675x50()2 IOOOSn - 1000(3250)2 Ps2Ufi _ 187.425X5002 1
27、000S IOOOx (3 250)2 _ 1428.8945002-IOOoS； - IOOoX (3x250)2=0.097()0.083()=0.635()XTlX24%以100Sn100Sn13.150021003250-2.35OO2100325031.55002=43.667()=-7.667()X 3 100Sn1003250Gt = r = 989 = 3.956 X10-7 (S) 100(W; 1000 5002/ = 0.08x3x250 = 24x10IOoU；IOO5OO2A涓 P2+2 /D .v、902 +56AWZT3 = -2-(&3 + jX3 ) = -5
28、0()2= 1O5()(0.635 + jl 05) = 0.029 + j4.719( M VA)S2 = ASZT3 +90 + j56 = 90.029 + j60.719(MVA)PRn + QXt3 _ 90x0.635 + 56x105U500PXTl - QRn 90105-560.635=1 L874(kV)500= 18.829(kV)U2 = (500+l 1.874)2 +18.8292 = 521.22(kV)4002 +19425zt2 =(0.083 - j7.667) = 0.066-j6.061(MVA)寸；=A6z2 + 400 + jl 94 = 400.0
29、66 + jl 87.939(M VA)400.066 0.083 +187.939 (-7.667)SU2512.22400.066 (-7.667)-187.939 0.083=-2.748(kV)512.22-6.019(kV)U2 = 512.22-(-2.748)2 +(-6.019)2 = 515.003(kV)中压侧电压：t.l. =U3230 (1-2.5%)500=230.979(kV)S; = S+S2 = 400.066 + jl 87.939+ 90.029 + j60.719 = 490.095 + j248.658(MVA)( =490.095x0.097 + 24
30、8.658x43：66Z = 2k29(kV)512.22= 41.734(kV)490.095 43.667 - 248.658 0.097512.22Ui = J(512.22 + 21.291)? + 41.734 = 535.14 l(kV) 高压侧电压：=U =535.141(kV) = = 0.13100 = 13()X =x1 = 0.4100 = 40()B =5/ = 2.8 X10 X100 = 2.8X104(S)电压归算到高压侧：U=UCX= = 200(kV)38.5802 +402ASzr = :(W) X(3.025 + j50.4) = 0.605 + jl 0
31、.08(MVA) = S2 + =80 + j40 + 0.605 + jl 0.08 = 80.605 + j50.08(MVA)AUzr = 11.29(kV)PRT + QXt 803.025 + 4050.4U-200汉zrPXLQRTU80 50.4-40 X 3.02520019.555(kV)U2 = a( + (7ct)2+z2 = 212.193(kV)S = (GT + jB )2 = (2.07 W6+ j29.7 106) 212.1932 = 0.093 + jl.337(MVA)5y2=-j2.810-4212J932 =-j6.30MVA) = + S + S2
32、= 80.698 +j45.113(MVA)An刊 R + Q；X 80.698 13 + 45.11340 -MJ7 = - = 13.448(kV)L U2212.193=P”达二 8069840-45113l3 二L U2212.193Ul = (72+(z)2z2 = 225.984(kV)a 82+。；280.6982 +45.1 132 z1. .zim . zl ,oSz = N - (R + jX) =22 .B2x(13 +j40) = 2.468 +j7.593(MVA)S=-j 2.8 104 225.9842 =-j7.15(MVA)51 = + 5z+S = 83.1
33、66+j45.556(MVA)即始端电压为225. 984kV,始端功率为(83. 166+j45. 556)MVAAB: RAB=O08 X 65 = 5.2(C)Xab =0.4165 = 26.65()Bab =2.710 6 65 = 1.755 10 4(S)B1 : /?B1 =0.10880 = 8.64()XBl=O42 X 80 = 33.6(。)Bbi = 2.69 10 6 80 = 2.152 10 4 (S)设全网电压为额定电压UN =22()kV ,计算功率分布：2()2 +1()2aa ,Stb = Sztb + 5ytb = 2202 X U 395 + j21
34、8.2)+ (1.729 106 j5.86 106) 2202=0.228 +j2.538(MVA)5b =ASTB + 20 + jl O = 20.228 + jl 2.538(MVA)402 + 302ASZT2 = 3； (1.46 + j) = 0.075(MVA)302 +202Sz3 = 2励2 X Q92 + jll 7.7) = 0.078 j3.161(MVA)S； = Sz2 +40 + j30 = 40.075 + j30(MVA) = Sz3 +30 + j20 = 30.078 + j23.161(MVA)5； = + = 70.153j53.161(MVA)Sz
35、 =察” X (1.46 + j48.9) = 0.234 + j7.828(MVA)S； = + 5z = 70.387+ j60.989(MVA)ASYT = (GT + JBT)Ua= (0.847 106+ j3.53 106) 2202 = 0.041 + jO. 171(MVA)S1 = S； + S = 70.428 + j61.16(MVA)Sybii = -j 2.152 10-4 2202 =-j5.208(MVA)S1ff= 51 +Sybii = 70.428 +j55.952(MVA)5zbi = 7422tf5,952 (8.64 + j33.6) = 1.444
36、+j5.617(MVA)ybi2 = -j 2.152 104 2202 =-j5.208(MVA) =S,*+Szbi = 71.872 +j61.569(M YA)5bi = +5ybi2 =71.872 +j56.361(MVA) =5bi +5b =71.872 + j56.361 + 20.228+ jl2.538 = 92.1 + j68.899(MVA)5yabi =-j1.755W42202 =-j4.247(MVA)S；B = + Syabi =92.1 + j64.652(MVA)92 I2 +64 6522Szb = 22 (5.2 + j26.65) = 1.36 +j6.972(MVA)Sab = S；B + Szab = 93.46 + j71.624(MVA)Syab2 = - j i 755 10-4 2422 =-j5.139(MVA)Sa = SAB + 5yb2 = 93.46+j66.458(MVA)用给定的始端电压和求得的功率分布，计算各段中的电压和变电所高压母
